Penentuan Warung Makan
Nilai Alternatif Setiap Kriteria
| ALTERNATIF | C1 | C2 | C3 | C4 | C5 |
|---|---|---|---|---|---|
| A1 = Warung Mang Ujang | 7 | 10000 | 6 | 9 | 150 |
| A2 = Warung Cinta Rasa | 9 | 11000 | 8 | 8 | 250 |
| A3 = Warung Padang | 6 | 9000 | 5 | 7 | 120 |
| A4 = Warung Bugis | 9 | 6000 | 7 | 8 | 100 |
| KRITERIA | benefit | cost | benefit | benefit | cost |
| BOBOT | 4 | 5 | 2 | 3 | 3 |
Tahap 1
Cari nilai W dan kalikan 1 untuk W yang bersifat keuntungan (benefit) dan kalikan dengan -1 untuk W yang bersifat biaya (cost)
W1 =
44 + 5 + 2 + 3 + 3 =
417 = 0.235
W2 =
54 + 5 + 2 + 3 + 3 =
517 = 0.294
W3 =
24 + 5 + 2 + 3 + 3 =
217 = 0.118
W4 =
34 + 5 + 2 + 3 + 3 =
317 = 0.176
W5 =
34 + 5 + 2 + 3 + 3 =
317 = 0.176
W1 (benefit) = 0.235*1 = 0.235
W2 (cost) = 0.294*(-1) = -0.294
W3 (benefit) = 0.118*1 = 0.118
W4 (benefit) = 0.176*1 = 0.176
W5 (cost) = 0.176*(-1) = -0.176
Tahap 2
Cari nilai S ternormalisasi setiap alternatif
S2 = (90.235)(11000-0.294)(80.118)(80.176)(250-0.176) = 0.0758
S3 = (60.235)(9000-0.294)(50.118)(70.176)(120-0.176) = 0.0768
S4 = (90.235)(6000-0.294)(70.118)(80.176)(100-0.176) = 0.1047
Tahap 3
Mencari Nilai V
Atau
V1 =
0.07930.0793 + 0.0758 + 0.0768 + 0.1047 =
0.07930.3366 = 0.2356
V2 =
0.07580.0793 + 0.0758 + 0.0768 + 0.1047 =
0.07580.3366 = 0.2252
V3 =
0.07680.0793 + 0.0758 + 0.0768 + 0.1047 =
0.07680.3366 = 0.2282
V4 =
0.10470.0793 + 0.0758 + 0.0768 + 0.1047 =
0.10470.3366 = 0.3111
Dari beberapa kandidat terpilih alternatif
A4 (Warung Bugis ) dengan nilai = 0.3111