Coffee shop
Nilai Alternatif Setiap Kriteria
| ALTERNATIF | C1 | C2 | C3 | C4 | C5 |
|---|
| A1 = coffee shop 1 | 45 | 4 | 5 | 4 | 4 |
| A2 = coffee shop 2 | 30 | 5 | 3 | 5 | 3 |
| A3 = coffee shop 3 | 25 | 3 | 4 | 3 | 5 |
| A4 = coffee shop 4 | 50 | 5 | 4 | 3 | 3 |
| A5 = coffee shop 5 | 35 | 3 | 5 | 5 | 4 |
| KRITERIA | benefit | benefit | benefit | benefit | benefit |
|---|
| BOBOT | 31 | 24 | 19 | 16 | 10 |
|---|
Tahap 1
Cari nilai W dan kalikan 1 untuk W yang bersifat keuntungan (benefit) dan kalikan dengan -1
untuk W yang bersifat biaya (cost)

W1 =
3131 + 24 + 19 + 16 + 10 =
31100 = 0.310
W2 =
2431 + 24 + 19 + 16 + 10 =
24100 = 0.240
W3 =
1931 + 24 + 19 + 16 + 10 =
19100 = 0.190
W4 =
1631 + 24 + 19 + 16 + 10 =
16100 = 0.160
W5 =
1031 + 24 + 19 + 16 + 10 =
10100 = 0.100
W
1 (benefit) = 0.310*1 = 0.310
W
2 (benefit) = 0.240*1 = 0.240
W
3 (benefit) = 0.190*1 = 0.190
W
4 (benefit) = 0.160*1 = 0.160
W
5 (benefit) = 0.100*1 = 0.100
Tahap 2
Cari nilai S ternormalisasi setiap alternatif

S
1 = (45
0.310)(4
0.240)(5
0.190)(4
0.160)(4
0.100) = 8.8375
S
2 = (30
0.310)(5
0.240)(3
0.190)(5
0.160)(3
0.100) = 7.5138
S
3 = (25
0.310)(3
0.240)(4
0.190)(3
0.160)(5
0.100) = 6.4343
S
4 = (50
0.310)(5
0.240)(4
0.190)(3
0.160)(3
0.100) = 8.5679
S
5 = (35
0.310)(3
0.240)(5
0.190)(5
0.160)(4
0.100) = 7.9071
Tahap 3
Mencari Nilai V

Atau

V1 =
8.83758.8375 + 7.5138 + 6.4343 + 8.5679 + 7.9071 =
8.837539.2606 = 0.2251
V2 =
7.51388.8375 + 7.5138 + 6.4343 + 8.5679 + 7.9071 =
7.513839.2606 = 0.1914
V3 =
6.43438.8375 + 7.5138 + 6.4343 + 8.5679 + 7.9071 =
6.434339.2606 = 0.1639
V4 =
8.56798.8375 + 7.5138 + 6.4343 + 8.5679 + 7.9071 =
8.567939.2606 = 0.2182
V5 =
7.90718.8375 + 7.5138 + 6.4343 + 8.5679 + 7.9071 =
7.907139.2606 = 0.2014
Dari beberapa kandidat terpilih alternatif
A1 (coffee shop 1) dengan nilai = 0.2251